4sin^2(2x)+16cos^2(2x)=

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Solution for 4sin^2(2x)+16cos^2(2x)= equation: 


Simplifying
4sin2(2x) + 16cos2(2x) = 0

Remove parenthesis around (2x)
4in2s * 2x + 16cos2(2x) = 0

Reorder the terms for easier multiplication:
4 * 2in2s * x + 16cos2(2x) = 0

Multiply 4 * 2
8in2s * x + 16cos2(2x) = 0

Multiply in2s * x
8in2sx + 16cos2(2x) = 0

Remove parenthesis around (2x)
8in2sx + 16cos2 * 2x = 0

Reorder the terms for easier multiplication:
8in2sx + 16 * 2cos2 * x = 0

Multiply 16 * 2
8in2sx + 32cos2 * x = 0

Multiply cos2 * x
8in2sx + 32cos2x = 0

Reorder the terms:
32cos2x + 8in2sx = 0

Solving
32cos2x + 8in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8in2sx' to each side of the equation.
32cos2x + 8in2sx + -8in2sx = 0 + -8in2sx

Combine like terms: 8in2sx + -8in2sx = 0
32cos2x + 0 = 0 + -8in2sx
32cos2x = 0 + -8in2sx
Remove the zero:
32cos2x = -8in2sx

Divide each side by '32os2x'.
c = -0.25in2o-1s-1

Simplifying
c = -0.25in2o-1s-1

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